pull substring from string in bash

JaredBusch

I have a working solution, but I'm not a master bash expert. Just a guy that uses it a lot.

Is there a better way to to what I am doing?
This is the source data.

      Jared Busch (Local/103@from-queue/n from hint:103@ext-local) (ringinuse enabled) (dynamic) (Not in use) has taken no calls yet
      Test_Extension (Local/121@from-queue/n from hint:121@ext-local) (ringinuse enabled) (Not in use) has taken no calls yet
      T46S - Demo 1 (Local/118@from-queue/n from hint:118@ext-local) (ringinuse enabled) (Not in use) has taken no calls yet

I need this part: Local/103@from-queue/n

I am getting it currently, like this: grep -o Local.*/n

Full sample:

[jbusch@pbx ~]$ rasterisk -x 'queue show 150' | grep -o Local.*/n
Local/103@from-queue/n
Local/121@from-queue/n
Local/118@from-queue/n

scottalanmiller

that's pretty good. Using cut would be another option. Not better, just an option.

JaredBusch

@scottalanmiller said in pull substring from string in bash:

that's pretty good. Using cut would be another option. Not better, just an option.

It's been running in script for a year to unpause queue agents. but i'm thinking about expanding it. so before I do that, I anted to make sure it was decent as is.

JaredBusch

said script

[jbusch@pbx ~]$ cat unpause_all.sh 
#!/bin/sh
set -e 

rasterisk -x "queue show ${1}" | grep paused | grep -o Local.*/n | while read -r member
do
    rasterisk -x "queue unpause member ${member} queue ${1}"
done

Solved pull substring from string in bash